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2w^2-29w+14=0
a = 2; b = -29; c = +14;
Δ = b2-4ac
Δ = -292-4·2·14
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-27}{2*2}=\frac{2}{4} =1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+27}{2*2}=\frac{56}{4} =14 $
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